Function to calculate the average size of a file in a directory in Bash?

Question

bash

We need to write a function to calculate the average size of a file in a directory. In this case, the function should check the directory for existence, and then display the average size of files in the directory. You also need to exclude subdirectories and symbolic links from the calculations.

I hit a dead end, and I can’t go further than this function ...
stat -c '%F %s' /mydir/.* *

Answer 1

find $1 -type f -ls|awk '{sum+=$7}END{print sum/NR}'

Answer 2

#!/bin/bash

# uncomment for debug
#set -x

function get_avg_size() {

  [ ! -d "$1" ] && echo "Directory $1 DOES NOT exists." && exit 1

  sum_size=0
  count=0

  for size in $(LC_ALL=C stat -c '%F %s' $1/* | grep 'regular file' | cut -d ' ' -f 3); do
    let sum_size=$sum_size+$size
    let count=$count+1
  done

  echo "Average file size $(($sum_size/$count))"
}

get_avg_size ~/

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