Function from the chart

Question

infographics

Services for plotting graphs from a function - darkness. I need a service / program where I could draw a graph, pull its curve, and so that a function of this graph is generated nearby. Want too much?

Answer 1

If you have given points (say, N+1 pieces) that you will pull, you can always construct an N degree polynomial that goes through these points. What you get will be a wild, mischievous and layy set of N+1 odds with very high precision, i.e. ∑a_n*x^n

Answer 2

Are you looking for a service/program or do you want to write it yourself?
If you want to write a program yourself that will build a function (in the form of a mathematical expression) and a graph (curve) based on a given set of points (i.e., for example, the user drew a graph by hand and then pulls some points of this graph up and down, and you need to convert this to a smooth curve and also display f(x) that will fit this graph), then the simplest for you, and still give the best results, would be the method of least squares, because it works well on sets that have random deviations in the values.
You can read, for example, here:
solidbase.karelia.ru/edu/meth_calc/files/09.shtm
But without knowledge of the basics of numerical methods, it is better not to even meddle in this area at all.
If you are not going to implement such an application, but you need a ready-made service, then, unfortunately, I can’t suggest anything.

Answer 3

So all the same - is there such a service?

Answer 4

Excel: trend line;
Eureqa (there is a trial of 30 days);
origin;
QtiPlot (trial 10 minutes each run).
Of the free ones, you should watch
Scilab;
Octave;
LabPlot (*nix only);
SciDAVis.
I used to use Excel for this, but now I use SciDAVis.

Answer 5

I would say yes. :-) The
maximum that comes to my mind is to program Taylor myself and somehow depict one or another >>UGGLE<< function on a particular site. Unfortunately, I don’t know how things are in MATLAB or Derive, but you can also get mad with 3-dimensional graphs in them.