Current distribution in parallel wires?

Question

Electronics

Google constantly tells me only about the magnetism of parallel wires. The situation is this, a twisted-pair wire, I want to send a current of 8 amperes through it, not through a pair, but just through this thin wire, and this is the question, if I connect another parallel wire of the same type to the source and consumer, will there be a current distributed between them, that is, it is clear that at the ends of the connection there will be 8 amperes, and in the wires themselves there will be 4 or also 8? And how can you achieve good high current carrying capacity if there are only such thin wires?
There was an idea to strip the wire, twist the strands into a thicker one and wind it with insulation itself, but it looks like insanity.

Answer 1

twisted pair wire, I want to put a current of 8 amperes through it,

Risky occupation, may cause a fire. Here the concept of current density plays the main role - a density of 5 ... 10 amperes / sq. mm is considered more or less safe (though it also depends on the cooling of this wire - the better it is, the greater the density is acceptable). Now take your wire. Its diameter is 0.5 mm, the cross section is ~ 0.2 sq. mm, and it turns out with your 8 amperes 40 amperes / sq. mm - four times the maximum value! Even if you bring the density to this maximum by stacking 4 of these wires together, keep in mind that the plastic insulation of these wires will most likely melt at this current (although the wire will most likely survive). The second drawback is that on such a wire at such a current a significant part of the voltage will sag, due to its increased resistance. Let's say give 220,

will the current be distributed between them

Currents in parallel branches will be distributed strictly according to their identity - if their resistances are equal, the currents will be strictly the same.

There was an idea to strip the wire, twist the strands into a thicker one and wind it with insulation itself, but it looks like insanity.

This is insanity. For your task, insulation does not matter, only the copper core matters, so include these cores in parallel, ignore the insulation. And take these veins not 4 (as in my example), but 8 ... 10 - then everything will be OK. And don’t even try (from my suggestion) to really apply a voltage of 220 volts to such a wire - twisted-pair wires have too weak insulation for such a voltage.

Answer 2

Do you have direct current or alternating current? The easiest way is to go to the store and buy a wire. 2 square millimeters is enough for you, copper, of course.
Although, it depends on the voltage and length. When it comes to twisted pair, I see that you need to read about PoE

Answer 3

Yes, it will be distributed, in theory it should be in half, but it depends on the resistance in the wire.
The passage of current depends on the area of ​​the conductor only up to a certain level, later the current passes along the outer side of the conductor, and then the area of ​​the conductor does not play a role. In your case, you can probably twist several pieces together.

Answer 4

Current 8A at what voltage?

Answer 5

The cross section of a twisted pair wire is about 0.2 sq. mm, you need about 0.8 - 1 sq. mm for such a current. That is, you need to connect 4-5 wires in parallel (the more, the better). Two won't be enough.