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css to jquery .css()?
How can I automate the copying of the css properties of an element from firebug or the chrome debugger, immediately in the css wrapper from jquery?
There are several dozen elements, you need to create it on the fly.
That is, with this code:
#simple {<br/>
background-color: red;<br/>
left:25%;<br/>
width: 50%;<br/>
height: 30px;<br/>
bottom: 0px;<br/>
}<br/>
.css({<br/>
backgroundColor: 'red',<br/>
left:'25%',<br/>
width:'50%',<br/>
height:'30px',<br/>
bottom:'0px',<br/>
})<br/>
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I found only a plugin that copies the ALL style of an object
/*
* getStyleObject Plugin for jQuery JavaScript Library
* From: http://upshots.org/?p=112
*/
(function($){
$.fn.getStyleObject = function(){
var dom = this.get(0);
var style;
var returns = {};
if(window.getComputedStyle){
var camelize = function(a,b){
return b.toUpperCase();
};
style = window.getComputedStyle(dom, null);
for(var i = 0, l = style.length; i < l; i++){
var prop = style[i];
var camel = prop.replace(/\-([a-z])/g, camelize);
var val = style.getPropertyValue(prop);
returns[camel] = val;
};
return returns;
};
if(style = dom.currentStyle){
for(var prop in style){
returns[prop] = style[prop];
};
return returns;
};
return this.css();
}
})(jQuery);
// Использовать так
var style = $("#simple").getStyleObject();
alert(JSON.stringify(style));
$('#simple-clone').css(style);
Did not meet, alas.
You can make yourself a page with an input field and listen to the change event of this field. And then execute:
function fix(css) {
if (!css) return false;
var obj = {};
css = css.split('\n').join('').split(' ').join('');
css = css.slice(css.indexOf('{') + 1, css.indexOf('}') - 1).split(';');
$.each(css, function(k, prop) {
prop = prop.split(' ').join('').split(':');
obj[prop[0]] = prop[1];
})
alert('.css(' + JSON.stringify(obj) + '})');
}
fix(_значение_из_поля_ввода_);
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