cmd. How to use findstr to display multiple lines in a row?

Question

cmd/bat

Got a team

certutil F:\\find\\3123.crl | findstr 0178dd6f0071aca5b6474113327488997f

The command looks for the serial number in the list of revoked certificates and returns a string if it is there. The
string is returned:

Serial number: 0178dd6f0071aca5b6474113327488997f

How to make search by serial number return all related rows.
The list itself looks like this:

Serial number: 01410749007EAC8FAD4FAP2A72239FEAFCA1 Date
of review: 25.11.2020 11:09
Expansion: 1
2.5.29.21: Flags = 0, Length Causion
Code (CRL)
Certificate Replaced (4)

Serial Room20
:45
Extensions: 1
2.5.29.21: Flags = 0, Length = 3
Revocation List (CRL) Reason Code
Replaced (4)

Serial Number: 019f296d007eac0ab04dcfeee27373ad6c Revocation
Date: 11/25/2020 9:40 AM
Extensions: 1
2.5.29.21: Flags = 0, Length = 3
Revocation list (CRL) reason code
Certificate replaced (4)

That is, you need to display all the lines until the empty one.

Answer 1

Loop, examples for your question are here:
https://www.cyberforum.ru/cmd-bat/thread786795.html

Answer 2

If certutil can display data only for a specific certificate from the revocation list, then you can call certutil again with a specific certificate by finding the desired serial number with your command.
Windows is not at hand now, I can not check my assumption.

Answer 3

It can be like this:

@echo off
certutil F:\\find\\3123.crl| find /v /n "">temp.txt
set "str=0178dd6f0071aca5b6474113327488997f"
for /f "delims=[]" %%1 in ('find "%str%"^<temp.txt') do  call :sub %%1
del temp.txt
exit /b

:sub
set /a skip = %1 - 1
for /f "skip=%skip% tokens=1,* delims=]" %%1 in (temp.txt) do (
  echo(%%2
  if "%%2"=="" exit /b
)

(If there are errors with the encoding, try adding the second or third line .) If you wish, you can do it without external utilities or ... chcp 1251>nul
findfindstr