Can UV/IR be converted to visible light?

Question

Working with color

Actually, I'm interested in a technology that will allow a person (who will wear special glasses) to see UV / IR (for example, UV violet, IR red) or at least one of them. The maximum that I found on the net is the concept of “acousto-optic modulator”, but they are difficult to get, plus, judging by the wiki, they are quite impressive in size.
I don't understand physics well. Is this even possible (I mean small inexpensive glasses)?

Answer 1

After reading the question "Can UV/IR be converted to visible light?" the first thing that came to mind was fluorescent lamps - they initially (at least in many) have UV inside them, and already the phosphor, absorbing UV, re-radiates in the visible spectrum. And according to the subject (the ability to “see” in this spectrum), you need a matrix that is sensitive to this range (if IR, then within certain limits you can use any camera by replacing the filter that cuts off the IR with a filter that only passes the IR)

Answer 2

Glasses in the form of lenses - hardly. You need a night vision device.

Answer 3

Any webcam/camera/cell phone camera will allow you to see IR.
Right now you can check on the remote control from the TV and the camera of the mobile.
Maybe that's why you should start digging.

Answer 4

A small note - UV (ultraviolet) type A, B or C? If UV-C then run, I'm not kidding.

Answer 5

Passive conversion, as far as I know, is not possible, since the wavelength must be changed, and passively you can only filter everything except a certain range. Therefore, just disassemble a thread of the camera and remove the IR and UV filters from there. Both are typically built into optics as coatings on lenses. But there are also hardware filters (in pro cameras). I don’t know about both ranges right away, but separately it’s easy.

Answer 6

Most likely not, because The schemes of work are, in theory, different for IR and UV (I do not consider manual adjustment using a camera, computer and monitors).
In addition, a number of substances will not let UV through.

Answer 7

There are designs of glasses with small monitors for everyday use. Google seems to be doing something in this direction. And then it’s simple: put a filter (glass) that passes only the waves you need, followed by a photomatrix (they have a tiny size), and display the result on monitors. It will probably cost as much as a plane.

Answer 8

I advise you to read about all sorts of EOPs. The principle is like in “night vision devices”.
At the input of the optics, we put filters that cut off the unnecessary range of wavelengths; we focus the image on the photocathode, the resulting electrons generate an avalanche of electrons in the MCP and finally fall on the screen covered with a phosphor. Everything - we "see the invisible."

Answer 9

And what is the question? Ordinary visible light can only be seen if it reflects off something or shines directly into the eye. If the option with reflection is suitable, we take any substance that glows in the UV and look (photoluminescence).

Answer 10

Too abstract statement of the problem, ala from Hollywood movies.
There are no such lenses in the simple version, so do not expect primitive glasses. If you need to see IR, then almost any photo / video recording device with a screen, or the same glasses (with screens) connected to the camera, saves. The dimensions of the chamber modules are tiny now, the price is low.
There are crystals that convert radiation of one frequency to radiation of another frequency, but this is expensive, difficult, and I'm afraid it won't work for you. You can read more about semiconductor lasers (some of the pointers just contain such elements)