Calculate % at different numbers (C#)?

Question

C++ / C#

Hello. There is this code:

double value = Convert.ToDouble(s);
double onePercent = value / 100;
value = value + onePercent * 10;
return value.ToString();

value = number + 10%.
How to make that, depending on the sum of the number, a unique% is added?
For example:
200 + 30%
600 + 25%
1000 + 20%
1400 + 15%
2000 + 10%

Answer 1

int arrayA[] = new int[5] { 200, 600, 1000, 1400, 2000 };
double arrayB[] = new double[5] { .3, .25, .2, .15, .1 };


for (int a = 0; a < arrayA.Length; ++a)
if (value == arrayA[a])
{
value += value * arrayB[a];
break;
}

spoiler

Да, можно было бы использовать словарь, но для новичка и два массива подойдут.

Answer 2

if, case ...
Explain the essence of the task, otherwise in the description it is not very clear what you want. What kind of condition, how should it be considered.

Answer 3

Do you need to add 10 percent to the number?
(Convert.ToDouble(s)*1.1).ToString()

Answer 4

Random to the rescue