C#. Why does the VK API return "photo":"[]"?

Question

Layout

I get:

{"server":627329,"photo":"[]","hash":"6ce9e707ba60a464bc45070a748dc9ec"}

private static HttpWebResponse PostMethod()
        {
            string url = "https://api.vk.com/method/photos.getMessagesUploadServer?&v=5.31&access_token=1234";
            WebClient client = new WebClient();
            string json = client.DownloadString(url);
            JavaScriptSerializer json_serializer = new JavaScriptSerializer();
            
            byte[] imageData = client.DownloadData("http://cs5530.vk.me/u43529379/-6/m_b9515ce2.jpg");
            RootObject response = (RootObject)json_serializer.Deserialize(json, typeof(RootObject));
           
            HttpWebRequest request = (HttpWebRequest)WebRequest.Create(response.response.upload_url);
            request.Method = "POST";
            request.Credentials = CredentialCache.DefaultCredentials;

            UTF8Encoding encoding = new UTF8Encoding();
            var bytes = encoding.GetBytes(imageData.ToString());

            request.ContentType = "multipart/form-data";
            request.ContentLength = bytes.Length;

            using (var newStream = request.GetRequestStream())
            {
                newStream.Write(bytes, 0, bytes.Length);
                newStream.Close();  
            }
            return (HttpWebResponse)request.GetResponse();
        }

Answer 1

input and its absolutely positioned label, all wrapped in a div.
Either outside the label, and inside the span.
Writing "email adress ..." in a pseudo-element is not appropriate.
Something like this: https://jsfiddle.net/m7hcbdrj/ colors, indents change as you need

Answer 2

Um... Style the fieldset ?

Answer 3

wrap the input in a div and apply pseudo-elements to it to display the caption on top

Answer 4

div>span+input and position as you want, or label instead of span

Answer 5

Use Fiddler and proxy all requests through it - this will help you quickly understand what the error is.
To get started, try loading the file in the browser on the method page and see how the request is formed in Fiddler, then check how your code works. The error will be visible almost immediately