Building a loop with an exception?

Question

Java

Goodnight.
There is a task - to sum up numbers from 1 to 100, excluding those that are divisible by 9 without a remainder. There is an idea that it is necessary to build in the form of two cycles - the first one checks for truth - whether the result of the division is int or double, the second one already performs the addition and displays the result. But how to organize - I can not figure it out.

Answer 1

public static void main(String[] args) {
        int sum = 0;
        for (int i = 1; i <=100; i++) {
             if(i%9 != 0 ){
                sum+=i;
            }
        }
        System.out.println("sum = " + sum);
    }

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for java 8 :

public static void main(String[] args) {
        int sum = IntStream.range(1, 100).filter(i -> (i%9!=0)).sum();
        System.out.println("sum = " + sum);
}

Answer 2

Kind.
if(i % 9 != 0) //if the remainder of division by 9 is not equal to zero
//then start summing