Awk how to parse output?

Question

linux

Good day!
It so happened that at work I have 10 petabytes of information, I need to identify video files with a bit rate> 30 megabits in this array and delete them!
How I played:
find . -not -name "*.wav" -not -name "*.png" -not -name "*.info" -not -name "*.wav.1" -not -name "*.mp3" -not - type d -type f -printf "%P " -exec mediainfo --Output='Video;%BitRate/String%' {} \;
!!!RENDER!!!/OUT/107_0286_03.MP4 4,514 b/s
!!!RENDER!!!/OUT/107_0286_04.MP4 4,514 b/s
!!!RENDER!!!/OUT/001-379. MP4 10 000 kb/s
!!!RENDER!!!/OUT/Camera 3_41.MP4 10 000 kb/s
!!!RENDER!!!/OUT/Camera 4_43.MP4 10 000 kb/s
!!!RENDER!! !/OUT/Camera 4_44.MP4 10 000 kb/s
!!!RENDER!!!
!!!RENDER!!!/OUT/Camera 2_39.MP4 10 000 kb/s
!!!RENDER!!!/OUT/Camera 1_41.MP4 10 000 kb/s
!!!RENDER!!!/OUT/Camera 4_45 .MP4 10 000 kb/s
What I achieved the most:
[email protected]:/media/40# find . -not -name "*.wav" -not -name "*.png" -not -name "*.info" -not -name "*.wav.1" -not -name "*.mp3" -not - type d -type f -printf "%P " -exec mediainfo --Output='Video;%BitRate/String%' {} \; | awk '{print$(NF-2)$(NF-1)}'
4514
4514
10000
10000
10000
10000
I need to display full paths (up to dot + extension) and if bitrate > 30000 delete files.
Tell me how to implement?