ASM, x86, Explain the line with the CMP command?

Question

Programming

Hello! Let me tell you right now, I am new to these things. I was digging with the help of a disassembler in the program, and then I came across a line:
cmp d,[ebp][-4],0FFFFE0BE
Please explain what it all means: where did d come from? because cmp just compares two numbers? Why is the last argument (by all logic - it should be int32) of 33 bytes: 0 + 32 bytes of number?
Background: just above this line, the function takes a local variable (ebp-4, let's call it v) and subtracts 10000 from it. Most of the v before subtraction has values ​​of ~1998. Those. 1998 - 10000 = -8002. But in the comparison command above - v is compared with FFFFE0BE .... if you invert this number, you get exactly 1F42(8002). I'm assuming this has something to do with UNSIGNED?

Answer 1

Probably means cmp D WORD PTR [Addr], Imm
goo.gl/GSaQic

Answer 2

UPD. I played around with the calculator ... it turns out that FFFFE0BE is -8002 ... then everything converges:

v -= 10000;
if(v <= -8002)
    // code

and with that the issue is closed. I will know))))
But questions with the team format remain.