An exception is thrown when it shouldn't. What is the problem?

Question

Java

The file contains data about RectButton (4 coordinates, state and text). You need to read them and create a new RectButton based on them

public static RectButton  readRectButtonFromTextFileSixLines(File file) throws IOException, WindowException {
        try (BufferedReader br = new BufferedReader(new InputStreamReader(new FileInputStream(file)))) {
            int[] array = new int[4];
            String state, text;
            array[0] = br.read();
            br.readLine();
            array[1] = br.read();
            br.readLine();
            array[2] = br.read();
            br.readLine();
            array[3] = br.read();
            br.readLine();
            state = br.readLine();
            text = br.readLine();
            return new RectButton(array[0], array[1], array[2], array[3], state, text);
        } catch (FileNotFoundException e) {
            throw new FileNotFoundException();
        } catch (UnsupportedEncodingException e) {
            throw new FileNotFoundException();
        } catch (IOException e) {
            throw new IOException();
        }
    }

But when creating an instance, an exception is thrown, although it shouldn't be

. What could be the problem?

Answer 1

String comparison in java is not done through == or !=, but through the String methodequals