A small question about the sh-script?

Question

linux

There is some script vars.sh :
export PATH=`pwd`/bin:$PATH
Working with it looks like this:

$ cd /some/working/dir<br/>
$ great_app args<br/>
&nbsp;&nbsp;error: not found!<br/>
$ cd /some/interesting/dir<br/>
$ ls bin<br/>
&nbsp;&nbsp;great_app<br/>
$ . vars.sh<br/>
$ cd /some/working/dir<br/>
$ great_app args<br/>
&nbsp;&nbsp;i'm working!<br/>

Since vars.sh uses pwd, it needs to be in the same folder as the script itself to run it.
And I want to run vars.sh from any folder, leaving the entire package ( vars.sh script and bin folder ) easily moved from one folder to another, in short, without absolute paths.
As a result, you want this:

$ cd /some/working/dir<br/>
$ . /some/interesting/dir/vars.sh<br/>
$ great_app args<br/>
&nbsp;&nbsp;i'm working!<br/>

My attempts did not lead to anything good, does anyone know how this can be done?

Answer 1

If I understood correctly:
export PATH=`dirname $0`/bin:$PATH


Answer 2

Better simpler - make yourself an alias or a function in ~/.bashrc.

Answer 3

Unfortunately, I did not fully understand the author. Would it be enough to add ./bin to PATNA?

Answer 4

I do this: at the beginning of the script, I set up the MY_DIR variable:
MY_DIR=`readlink -f "$(dirname "$0")"`
Now it will contain the full path to the script, regardless of where it was launched from. Run other scripts already relative to this directory. I think this is preferable to modifying PATH (albeit temporarily).
Yes, please note: all quotes are required.

Answer 5

What an old horror question, nevertheless I will offer my own version:

SCRIPT_NAME=${0##*/}
SCRIPT_DIR="$( cd "$( dirname "${BASH_SOURCE[0]}" )" && pwd )"
FULL_SCRIPT_NAME=${SCRIPT_DIR}/${SCRIPT_NAME}
echo ${FULL_SCRIPT_NAME}

You can thus get the full path to the directory where the script was launched from, as well as the full name of the script with the path.