Why, when two ways of specifying the same list, does it take up a different amount of memory?

Question

Python

>>> a = [[i for i in range(0, 5)] for j in range(0, 2)]
>>> a
[[0, 1, 2, 3, 4], [0, 1, 2, 3, 4]]
>>> sys.getsizeof(a)
96

>>> a = [[0, 1, 2, 3, 4], [0, 1, 2, 3, 4]]
>>> a
[[0, 1, 2, 3, 4], [0, 1, 2, 3, 4]]
>>> sys.getsizeof(a)
80

Answer 1

list() uses more memory than list comprehension

Answer 2

because they are different objects... in the first case it is a list generator, in the second it is a list
>>> a = [[i for i in range(0, 5)] for j in range(0, 2)]
>>> a
[[0, 1, 2, 3, 4], [0, 1, 2, 3, 4]] >>>
sys.getsizeof(a ) memory that is directly occupied by the generator itself ...