Why when outputting “< ?php? >" via echo, are the tags commented out?

Question

PHP

This is all just an example, in fact, when I replace {% and %} with < ?php ? > outputs
Code:

echo '<?php if(2==2): ?> <div> LOL </div> <?php endif; ?>';

output:

How to fix (Should work without eval ) ?

Answer 1

1. get rid of the template,
or
2. write additional tags for the template engine to recognize the insertion of pure php code.