Why is the result of the function execution incorrect?

Question

C++ / C#

A number is called perfect if the sum of all its divisors is equal to itself. You need to write a search for such numbers in the entered interval.

int a, b;
cin >> a >> b;

  printf("Perfect numbers of range [%d;%d]:\n", a, b);
  for (int i = a; i <= b; i++)//перебор всех чисел в интервале
  {
    int sum = 0;//при каждом новом числе сумма обнуляется
    for (int j = 2; j < abs(i); j++)
      if (abs(i) % j == 0)//делитель - число, которое делит первичное число без остатка
      {
        sum += j;
      }
    if (sum == i)
      cout << i << '\t';
  }

The result is always 0. What ranges just did not take. What logical error did you make?
Yes, I know that it will not work for negative numbers, because the sum will always be positive. But even with positive numbers, the algorithm does not work correctly.

Answer 1

A perfect number (ancient Greek ἀριθμὸς τέλειος) is a natural number equal to the sum of all its own divisors (that is, all positive divisors other than the number itself ).

Forgot the unit. She is also a divider.