Why is the editMessageText function not working?

Question

JavaScript

Hello! Please help me find the error.
So we have the ban function. It works, but for some reason it doesn't want editMessageText to work.
The error is TelegramError: ETELEGRAM: 400 Bad Request: there is no text in the message to edit.

module.exports = async function(bot, message, query) {
    let ban = await Ban.findOne({
        where: {
            chat_id: query.data.split("_")[1]
        }
    });
    if(ban) {
        console.log(`Пользователь уже в бане`);
        return;
    }
    else {
        if (query.data.startsWith("ban")) {
            let ban = await Ban.create({
                chat_id: query.data.split("_")[1],
                unban: 3e15
            });
 
            if (ban) {
                console.log(`Пользователь undefined забанен вручную`);
                await bot.sendMessage(ban.chat_id, "Вы заблокированы в боте.");
                await bot.editMessageText("Пользователь заблокирован", {
                    chat_id: message.chat.id,
                    message_id: message.message_id
                });
            }
        }
    }

However!!! There is a similar function unbanned. Everything works there.

module.exports = async function(bot, message, query) {
    if (query.data.startsWith("unban")) {
        let ban = await Ban.findOne({
            where: {
                chat_id: query.data.split("_")[1]
            }
        });
 
        if (ban) {
            console.log(`Пользователь undefined разблокирован`);
            await ban.destroy();
            await bot.sendMessage(ban.chat_id, "Вы разблокированы в боте!");
            await bot.editMessageText("Пользователь разблокирован", {
                chat_id: message.chat.id,
                message_id: message.message_id
            });
        }
    }
}

Answer 1

You have a check if ban return, and then else and in it again if ban, when the user's BAN script enters the first if does console.log(`The user is already in the ban`); and return; the function will no longer work.