Why is the code marked as unreachable by the debugger?

Question

Java

Does the debugger mark code as unreachable? Because of this, the exchange over the network does not work.

package com.company.Network;

import java.io.*;
import java.net.*;
import java.util.LinkedList;

import Old.Message.Message;
import Tubes.Tube;

/**
 * @class Network
 * класс-поток для работы с сетью
 */

public class Network implements Runnable {
    private Tube m_in;
    private Tube m_out;

    private final int       m_port = 1300;
    private ServerSocket    m_serverSocket;
    private int             m_netType;
    private boolean         m_flag;
    LinkedList<Socket>      m_clientSocketsServers;
    Socket                  m_clientSocket;

    public Network() {
        m_netType = -1;
        m_flag    = true;
        m_clientSocketsServers
                = new LinkedList<Socket>();
    }

    public void stayServer() {
        m_netType = 0;
        try {
            m_serverSocket = new ServerSocket(m_port, 0,
                    InetAddress.getByName("localhost"));
        } catch (IOException e) {
            System.out.println(e.toString());
        }
    }

    public void stayClient() {
        m_netType = 1;
        while (m_flag) {
            try {
                m_clientSocket = new Socket(InetAddress.getByName("localhost"), m_port);
                break;
            } catch (UnknownHostException e) {
                System.out.println("Неизвестныйхост: " + "localhost");
                continue;
            } catch (IOException e) {
                System.out.println("Ошибка ввода/вывода при создании сокета " + "localhost"
                        + ":" + m_port);
                continue;
            }
        }
    }

    public void stopNet() {
        m_flag = false;
    }

    ///метод обмена информацией
    @Override
    public void run() {
        if(m_netType == -1) {
            return;
        }

        //as server
        if(m_netType == 0) {
            Socket clientSocket;
            InputStream in      = null;
            while (m_flag) {
                //чтение пришедших строк
                for (Socket ins : m_clientSocketsServers) {
                    try {
                        BufferedReader reader
                                = new BufferedReader(new InputStreamReader(ins.getInputStream()));
                        while (true) {
                            String ln = reader.readLine();
                            if(ln == null) {
                                break;
                            }
                            System.out.println(ln);
                            System.out.flush();
                        }
                        int p = 0;
                    } catch (IOException e) {
                        System.out.println("Ошибка при чтении сообщения.");
                        continue;
                    }
                }

                try {
                    clientSocket = m_serverSocket.accept();
                    m_clientSocketsServers.add(clientSocket);
                } catch (IOException e) {
                    continue;
                }
            }
        }

        //as client
        if(m_netType == 1) {
            OutputStream out     = null;
            PrintWriter writter  = null;
            try {
                out = m_clientSocket.getOutputStream();
                writter = new PrintWriter(out);
            } catch (IOException e) {
                System.out.println("Не удалось получить поток вывода.");
            }

            for(int i = 0; i < 10; i++) {
                writter.write(i);
                writter.flush();
            }
        }
    }
}

Answer 1

The code is unreachable because the while(true) expression specifies a compile-time constant as a condition, and no runtime checks are performed at this step. The debug point can be placed on the first line inside the loop. If the code doesn't work, that's not the reason.
PS Closing the line on the screenshot that causes the problem with a bubble with a description is evil.

Answer 2