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HellWalk2017-07-27 18:54:33
Yii
HellWalk, 2017-07-27 18:54:33

Why doesn't it display any information from the widget?

This is my first time making a widget in Yii2. At first, I practiced on pure Yii2 Basic - everything works. The widget is very simple, essentially just static code.
I'm trying to make a similar widget on a working project - I'm facing a strange problem. If you write die in a widget or its view; - the page template breaks (ie die; works and breaks the page), but the output of any other information, the same echo '123123'; does not lead to any result.
If you do:
echo '123123';
die;
That 123123 displays. What can be in the functionality of a widget, or page output, that ignores the output from the widget?

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3 answer(s)
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Maxim Timofeev, 2017-07-27
@webinar

1. Why do you need die;? It terminates the script. Not a widget, just a script (yii)
2.

ignores the output from the widget
show the widget, why did you decide that something is being ignored there?

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Abdula Magomedov, 2017-07-27
@Avarskiy

The widget returns output data. I think you are calling the widget incorrectly!

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