Why doesn't console.log show up like gulp ends a function?

Question

JavaScript

What is the correct way to write console.log('END') after gulp.task completes?

const { src, dest, series } = require('gulp');
const sass = require('gulp-sass');

function OPTcompileSCSS() {
  console.log('START');
  return src('src/assets/scss/**/*.scss')
    .pipe(sass().on('error', sass.logError))
    .pipe(dest('build/test/assets/css/'));
  // console.log('END'); // не работает, не отображается в консоли.
}

exports.OPTcompileSCSS = OPTcompileSCSS;

Answer 1

You are trying to console.log after the function has exited.
You should wrap the call to the function itself in console.log.

console.log('START')
OPTcompileSCSS()
console.log('END')

Well, most likely you want to measure the execution time of a function, use console.time(label) and console.timeEnd(label) for this

console.time('OPTcompileSCSS')
OPTcompileSCSS()
console.timeEnd('OPTcompileSCSS')