Why doesn't bash show a variable inside echo when run from Cron?

Question

bash

There is a script

#!/bin/bash 

RESULT=$(/usr/local/bin/wp core verify-checksums --allow-root --path=/var/www/web/)
IS_OK=${RESULT:0:7}

if [ "$IS_OK" == "Success" ]; then
    echo "No problem found. Have a nice day!"
else
        echo "Problem is: >>> $RESULT <<<"

     fi

When launched manually, $RESULT is substituted with the answer from

/usr/local/bin/wp core verify-checksums --allow-root --path=/var/www/web/

When run via Cron, $RESULT is always empty. Why?

Answer 1

When run via Cron, $RESULT is always empty.
Why?

Most likely because it is not possible to start /usr/local/bin/wp. For variety, you can do this:

RESULT=$(/usr/local/bin/wp core verify-checksums --allow-root --path=/var/www/web/ 2>&1 )

to see the full output of the command.
In addition, commands usually set the exit status based on success/failure. It can be obtained from $?. And if /usr/local/bin/wp does everything right, then the IS_OK part can be rewritten like this:

IS_OK=$?
if [ $IS_OK == 0 ]; then