Why does vector::end() return a const_iterator?

Question

C++ / C#

class SomeType{
    std::vector<AnotherType> _items;
public:
    void removeItem(AnotherType *pItem);
};
void SomeType::removeItem(AnotherType *pItem) {
    auto found = std::find(_items.begin(), _items.end(), *pItem); // error
    //....
}

GCC swears at the line with the search:

C:\Qt\Tools\mingw492_32\i686-w64-mingw32\include\c++\bits\predefined_ops.h:191: ошибка: no match for 'operator==' (operand types are 'AnotherType' and 'const AnotherType')
  { return *__it == _M_value; }
                 ^

Why is end overload allowed if _items is not a constant vector?

Answer 1

And where did you get the idea that end returns a const_iterator? If it returned a constant iterator, then the types in error would be 'const AnotherType' and 'const AnotherType'
Correct the comparison operator so that it takes objects by constant reference.