Why does this code work as I expect?

Question

go

What exactly does not work as I expect. I am new to GO.

I have an infinite loop that I start and stop by sending a message to m[1] channel. But here's what's not clear, I'm passing go loop(m[1]); not by reference as far as I understand. Why when I send a message to m[1] it gets into the loop that was called before the building where I send the message.

I thought that this should be called with & or similar.

package main

import (
  "fmt"
  "time"
)

func loop(quit chan bool) {
  n := 0
  for {
    select {
    case <-quit:
      break
    default:
      // do stuff. I'd call a function, for clarity:
      fmt.Println(n)
      time.Sleep(500 * time.Millisecond)
      n++

    }
  }
}

func main() {
  m := make(map[int]chan bool)

  m[1] = make(chan bool)
  go loop(m[1]);
  time.Sleep(2 * time.Second)
  m[1] <- true
}

Answer 1

Because after sending the true message to the channel, the function (goroutine) main ends and the application (everything) stops.