Why does the remove function from an array not work?

Question

Python

If there is an answer to the following question, you can stop reading further:
Why is it the value that is removed, and not the index of the remove function?
array.remove(index)
_________________________________________________________________________________

array = [1, 0, 2, 0, 3, 4, 5, 0, 6, 7, 8, 9]
print("До удаления", array)
c = 0
Array_counter = []
for i in range(len(array)):
    if array[i] == 0:
        Array_counter.append(i)
        c = c+1
print("Array_counter = ", Array_counter)
for k in range(0, c):
    m = Array_counter[k]
    print("Индекс элемента с нулевым значением = ", m)
    array.remove(m)  # удаляем 0 с индексом m
print("Удалили все нули", array)

Output:
Before removal [1, 0, 2, 0, 3, 4, 5, 0, 6, 7, 8, 9]
Array_counter = [1, 3, 7]
Index of element with null value = 1
Index of element with null value = 3
Index of element with zero value = 7
Removed all zeros [0, 2, 0, 4, 5, 0, 6, 8, 9]

Answer 1

>>> a = [1, 2, 3, 4, 5]
>>> a.remove(3)
>>> a
[1, 2, 4, 5]
>>> del a[3]
>>> a
[1, 2, 4]

Answer 2

Each time after the deletion, the indices of the remaining zeros (and all other elements with indices greater than the index of the element being deleted) are changed, shifted to the beginning of the array.

Answer 3

Agree with LaRN ...
...and of course, use del instead of remove, because
" list. remove(x) removes the first element in the list that has the value x " ;) - so remove just works :)
In this case, the minimum code change would be:

...
for k in range(0,c)[::-1]:
    m = Array_counter[k]
    print("Индекс элемента с нулевым значением = ", m)
    del(array[m])  # удаляем 0 с индексом m
...