Why does gulp-uglify produce such a result?

Question

JavaScript

Task

gulp.task('js', function() {
  return gulp.src([
    'assets/app/libs/jquery/dist/jquery.min.js',
    // Всякие библиотеки
    'assets/app/js/common.js', // Всегда в конце
    ])
  .pipe(concat('scripts.min.js'))
  .pipe(uglify())
  .pipe(gulp.dest('assets/app/js'))
  .pipe(browserSync.reload({stream: true}));
});

I write in common.js

$(".form").submit(function(e) {
    e.preventDefault();

    var th = $(this),
        reqInputs = th.find(".required")

    for (var i = 0; i < reqInputs.length; i++) {
      reqInputs[i].addClass("error")
    }

  });

And what do I get in scripts.min.js

$(".form").submit(function(e){e.preventDefault();for(var t=$(this),n=t.find(".required"),i=0;i<n.length;i++)n[i].addClass("error")})

What happened to the loop and variable names?

Answer 1

What's wrong with them? Everything shrank very well.