Why can foo[len(foo):]?

Question

go

foo := [5]int{0, 1, 2, 3, 4}
fmt.Println(foo[:5]) //так можно
fmt.Println(foo[5:]) //и так
fmt.Println(foo[5])  //так нет. Почему?
//Где это документировано? Как это понимать

https://play.golang.org/p/J55-p3hW_tB

Answer 1

You are wrong about the lack of documentation on this topic

a[2:]  // same as a[2 : len(a)]
a[:3]  // same as a[0 : 3]
a[:]   // same as a[0 : len(a)]

Answer 2

Because this is a call to a non-existent 5th element in the array. Addressing starts at index 0 and the element with index 4 is the last one in it. The first border is included in the slice; the latter is not included, so we write - this is an empty slice, you can also get it like this: or like this:foo[5]
fmt.Println(foo[1:1])

Answer 3

https://dribbble.com/

Answer 4

A selection of works from popular sources: flatun.com

Answer 5

behanes, dribble

Answer 6

here are the coolest
https://www.awwwards.com/

Answer 7

Be inspired by everything, but not by other people's interfaces, because it will be just copying. This is a dead end development.

Answer 8

develop a sense of taste, at least pay attention to all the graphics on the streets of your city