Which webcam to choose for recording lectures?

Question

Video

The recording will be in HD, on a Mac Air 2010 laptop, Sony Vegas software.
Shooting only indoors, the width of the shooting area is 3-4 meters, i.e. about 3-5 meters between the camera and the object.
The microphone is most likely a separate external one.
There are no outlets, so a laptop and a webcam, the camera does not have enough battery for 2-3 hours of shooting. Natural lighting (panoramic windows).
A cursory search on the Internet gave two leaders: Logitech 9000 pro (but the sound is mono) and Logitech C910 (but 15 fps instead of the declared 30 and does not always focus beyond 2 meters).

Answer 1

You cannot find an error because the structure and logic of the program is not built. Here is a simple solution "on the forehead" using a minimum of funds. The class allows you to get rid of the clutter of formulas that is difficult to perceive:

class Match:

    @classmethod
    def from_coords(cls, coords):
        yield cls(coords[0:2])
        yield cls(coords[2:4])
        yield cls(coords[4:6])

    def __init__(self, endpoints):
        self.x1, self.x2 = sorted(endpoints)
  
    def __invert__(self):
        return self.x2 - self.x1
    
    def __xor__(m1, m2):
        return max(m1.x2, m2.x2) - min(m1.x1, m2.x1) - ~m1 - ~m2
    
    def __and__(m1, m2):
        return m1 ^ m2 <= 0

        
def solve(*coords):
    m1, m2, m3 = Match.from_coords(coords)
    if (m1 & m2) + (m1 & m3) + (m2 & m3) >= 2:
        return 0
    if ~m1 >= m2 ^ m3:
        return 1
    if ~m2 >= m1 ^ m3:
        return 2
    if ~m3 >= m1 ^ m2:
        return 3
    return -1


if __name__ == '__main__':
    
    assert solve(0, 2, 4, 5, 3, 6) == 1
    assert solve(1, 2, 9, 10, 12, 20) == 3
    assert solve(1, 5, 0, 1, 4, 8) == 0
    assert solve(1, 3, 3, 4, 5, 6) == 1
    assert solve(0, 1, 3, 5, 9, 10) == -1