What to do Python Vk api request not working?

Question

Python

import vk
import json
import time

user_password='*********'
user_login='*********'
app_id='*********'

session=vk.AuthSession(app_id=app_id,user_login=user_login,user_password=user_password,scope='messages')
api =vk.API(session)




chat_id= 26
print("Начало работы")
print("Захожу в беседу")
print("Добавляю тебя в беседу")
r = api.messages.addChatUser(chat_id=chat_id,user_id=242352092)
time.sleep(1)
if r!=1:
    print("Ошибка,не удалось тебя добавить в беседу")
    api.messages.removeChatUser(chat_id=chat_id,user_id=381887204)
    print("Вышел из беседы")
else:
    api.messages.removeChatUser(chat_id=chat_id, user_id=381887204)
    print("Вышел из беседы")

Is this the kind of mistake I have to make?
tried to write an antikick from the conversation

Traceback (most recent call last):
  File "C:/Users/kirill/Desktop/Божеские разаработки на Python/Антикик из беседы/main.py", line 19, in <module>
    r = api.messages.addChatUser(chat_id=chat_id,user_id=242352092)
  File "C:\Users\kirill\AppData\Local\Programs\Python\Python36-32\lib\site-packages\vk\api.py", line 173, in __call__
    return self._api._session.make_request(self)
  File "C:\Users\kirill\AppData\Local\Programs\Python\Python36-32\lib\site-packages\vk\api.py", line 102, in make_request
    raise error
vk.exceptions.VkAPIError: 10. Internal server error. request_params = {'oauth': '1', 'method': 'messages.addChatUser', 'chat_id': '26', 'user_id': '242352092'}

Answer 1

Obviously, the user is not an administrator of the conversation. If you are excluded from the conversation, then you will not be able to return to it yourself.