What is wrong with the search algorithm?

Question

Java

I wanted to implement a file search algorithm to find all matches:
All matches will be output to the find variable of ArrayList type. Below is the algorithm itself.

spoiler

package com.filefind;

import java.io.File;
import java.util.ArrayList;
import java.util.List;

public class Find {
    public static void main(String args[]) {
        long start = System.currentTimeMillis();
        try {

            ArrayList<File> find = new ArrayList<>(200);
            findFile("D:\\Autodesk", find, "README");
                find.forEach(System.out::println);
        }
        catch (NullPointerException error) {
            System.out.println("File not found!");
        }
        long end = System.currentTimeMillis();
        System.out.println("Поиск занял: " + (double) (end - start) / 1000 + " секунд");
    }

    public static void findFile(String path, List<File> result, String name) {
        if (!path.endsWith("\\"))
            path += "\\";
        File list[] = (new File(path)).listFiles();
        for (File file : list) {
            if (file.getName().contains(name))
                result.add(file);
            if (file.isDirectory())
                findFile(path + file.getName() + "\\", result, name);
        }
    }
}

There are n files on the D:\ drive. If you drive in a specific folder on this drive (ie D:\Folder1\), then the search works quickly and gives the correct result. If the path argument is set to D:\, then the search is performed for 5-10 seconds and a NullPointerException is thrown, however, all files and folders on the D:\ drive are run through. A search through Windows Explorer showed that 80 files containing the text README are stored on the disk. Why is null stored in the find variable after the run?
upd: Solved the problem. File search algorithm code:

spoiler

/** Функция поиска файлов в каталогах
     * @param path - путь, в котором следует выполнить поиск
     * @param result - в списке result будут храниться все совпадения
     * @param name - имя файла, которое следует найти
     */
    private static void findFile(String path, List<File> result, String name) {
        if (!path.endsWith("\\"))
            path += "\\";
        File list[] = (new File(path)).listFiles();
        if (list == null) return; // если listFiles() возвращает null, значит не удалось прочитать текущую папку (ограничение доступа в системе)
        for (File file : list) {
            if (file.getName().toLowerCase().contains(name.toLowerCase()))
                result.add(file);
            if (file.isDirectory())
                findFile(path + file.getName() + "\\", result, name);
        }
    }

Answer 1

What's in the list[] variable for D:\?
PS: Path separator in Java is cross-platform and regardless of the OS, you should use '/'
Also, in order not to track these slashes when concatenating file names, it's better to use the File(File, String) constructor

Answer 2

I think I have found the cause of the error. I have one hidden folder on my D:\ drive, access to which is restricted by the system. That is why when trying to read this folder, an exception takes off. Now the question is: how do I programmatically catch folders that are restricted? Use try..catch or is there another way to implement it?
upd: Solved the problem. For some reason, the canExecute() method did not help, but I noticed that if the listFiles() method passes null, then reading this folder is impossible, so we just exit the method.