What is wrong with the php code?

Question

PHP

This crap first gives out 4, then 3 and that's it.

$f = fopen("db.txt", "r"); 	
$c = $f + 1;
fclose($f);
$f = fopen("db.txt", "w"); 	
fwrite($f, $c); 	
fclose($f);
echo $c;

Where is the mistake?

Answer 1

If I understood correctly what you wanted to write, then:

<?php
$fd = fopen("db.txt", "r");
$data = fgets($fd);
fclose($fd);
$data = $data + 1;
$fd = fopen("db.txt", "w");
fwrite($fd, $data);
fclose($fd);
echo $data;

You missed fgets.
And remember that for the meaningless names of variables in a decent society they can even heat up with a candelabra.

Answer 2

I hope not offtopic, but I'll leave it here:
Once
php.net/manual/ru/function.file-get-contents.php
and two
php.net/manual/ru/function.file-put-contents.php

Answer 3

fopen returns a resource type, why are you trying to do arithmetic with it?

Answer 4

You can also use fread to read the contents of a file. fopen - opens, and fread or fgets fetches the contents. With variable names +1

Answer 5

How did you get into the past? lol :)

Answer 6

maybe something like that?

file_put_contents( 'db.txt' , $data = (int)file_get_contents('db.txt') + 1 );
echo $data;