What is the correct way to write ListenAndServeTLS() with a custom servemux type?

Question

go

Swears that there are many arguments in ListenAndServeTLS().

How to write correctly? And why are there only two arguments in this case (in the documentation-syntax for ListenAndServeTLS()- 4)?
The code:

func main() {
    var mux = http.NewServeMux()
    mux.HandleFunc("/", indexPage)
    var serv = &http.Server {
        Addr:         serverPort,
        ReadTimeout:  15 * time.Second,
        WriteTimeout: 15 * time.Second,
    }
    log.Fatal(serv.ListenAndServeTLS(TLScert, TLSkey, mux))
}

Answer 1

You call the ListenAndServeTLS method on the Server struct, it has only two parameters.
The four parameters of the ListenAndServeTLS method for the http package.
You need to add the Handler: mux parameter to the struct, and call the ListenAndServeTLS method of the Server struct. You should end up with something like this:

func main() {
    var mux = http.NewServeMux()
    mux.HandleFunc("/", indexPage)
    var serv = &http.Server{
        // добавляете параметр
        Handler:      mux,
        Addr:         serverPort,
        ReadTimeout:  15 * time.Second,
        WriteTimeout: 15 * time.Second,
    }
    // вызываете с двумя параметрами
    log.Fatal(serv.ListenAndServeTLS(TLScert, TLSkey))
}