What is the correct way to sort an array of objects?

Question

Java

Please tell me what I'm doing wrong, I can't figure it out. You need to sort the strings by length.

package lesson6;


import java.util.Scanner;

public class Student {
  String name;
  
  
  
  
public static Student[] createMass(int n){
  Scanner sc1=new Scanner(System.in);
  System.out.println("Введите количество строк");
  if(sc1.hasNextInt()){
  n=sc1.nextInt();	
  }
  Student[] mass = new Student[n];
  for(int i = 0;i<mass.length;i++){
    mass[i] = new Student();
    mass[i].create();
    
  }
  return mass;
}

public   void create(){
  Scanner sc = new Scanner(System.in);
  System.out.println(" Введите имя ");
  if(sc.hasNextLine()){	
  name = sc.nextLine();
  if(name.endsWith("end")){
    name=" ";
  }
  }
  }	
  
  
  
  
public static void showMas(Student[]mass){
  for(int i=0;i<mass.length;i++){
    System.out.print("["+i+"]");
    mass[i].show();
  }
  
}
public void show(){
  System.out.println(name);
}
public void show1(Student[]mass){
  for(int i=0;i<mass.length;i++){
    System.out.print("["+i+"]");
  }
}
public static void sartirovka(Student mass[]){
  for(int j = 0; j<mass.length;j++){
    for( int i = j+1;i<mass.length;i++);{
      if( mass[i].compareTo( mass[j])<0){
        Student t = mass[j];
        mass[j] = mass[i];
        mass[i] = t;
        
        
      }
    }
  System.out.println(mass[j]);
      }
    }

Answer 1

Stream.of(mass)
        .sorted((m1, m2) -> m1.name.length() < m2.name.length() ? -1 : 1)
        .toArray();

If I understand correctly that you need to sort the array of students by the length of the name.

Answer 2

This problem is solved with the help of interfaces.
But, judging by how sloppy and confusing the code is, you'd better start learning Java from the very basics.