What does the error mean: You must build your code with position independent code if Qt was built with -reduce-relocations?

Question

Qt

When compiling in FreeBsd, I got the error "You must build your code with position independent code if Qt was built with -reduce-relocations" as if I know the literal translation, but what this means is not clear. Well, an additional postscript from the collector: "Compile your code with -fPIC or -fPIE" f what is clear, but what is PIC or PIE is not

Answer 1

This pair of options (exactly a pair, the manual advises using both to obtain predictable results) is just an instruction to the assembler to produce code that does not depend on its location in memory
to a different base address, all moves will fail, and the code will not work. These options will force the linker to use only relative addressing of program code.