What does [2] do in the given .match?

Question

JavaScript

There is this code:

host_uri.path().match(///^\/([a-z]*\/[a-z].*?\/[a-z].*?)-(.*).*///)[2]

I can't understand what [2] does, I also have an error: "Uncaught TypeError: Cannot read property '2' of null", and I can't figure out where this property is.

Answer 1

[2] does not apply to the regular season at all. This is an array element selection. Since matchin JS (and in all implementations) it returns an array, you simply select the 3rd element. That is:
/^\/([az]*\/[az].*?\/[az].*?)- (.*).*/
What you have there is known only to you.
But now you are trying to take the second 3rd element from Null