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What could be the problem with Run-Time Check Failure #3?
#include "pch.h"
#include <iostream>
#include <math.h>
using namespace std;
const double eps = 0.00001;
double _pow(double a, double b) {
double c = 1;
for (int i = 0; i < abs(b); i++) c *= a;
if (b < 0) c = 1 / c;
return c;
}
double _fact(double x) {
if (x < 0) return 0;
if (x == 0) return 1;
else return x * _fact(x - 1);
}
double _sin(double x) {
double a = x, s = x;
int n2 = 1;
while (fabs(a) > eps){
a = ((-a)*x*x) / ((n2 + 1)*(n2 + 2));
s += a;
n2 += 2;
}
return s;
}
double _cos(double x) {
double a=1.0, s=0.0;
int p = (int)s;
while (fabs(a) > eps) {
s += a;
p++;
a = ((-a)*x*x) / ((2 * p - 1)*(2 * p));
}
return s;
}
double _tan(double x) {
return (_sin(x) / _cos(x));
}
double proverka(double x1,double x2) {
int b=0, c=0;
if (x1 + x2 != -b && x1*x2 != c) cout << NULL << endl;
else cout << "1" << endl;
return x1,x2;
}
int main() {
cout << "Vvedite zadachu kotoruyu nado proverit :" << endl;
int h;
cout << "2ZADACHA-1" << endl; cout << "1ZADACHA-2" << endl;
cin >> h;
switch (h) {
case 1: {
cout << "Enter A, B, C:\n";
int a = 0, b = 0, c = 0;
cin >> a >> b >> c;
double x1, x2;
int discriminant = 0;
discriminant = ((int)_pow(b, 2)) - 4 * a * c;
if (discriminant > 0 && a != 0) {
x1 = ((-b - sqrt(discriminant)) / 2 * a);
x2 = ((-b + sqrt(discriminant)) / 2 * a);
cout << x1 << x2 << endl;
}
else if (discriminant = 0 && a != 0) cout << "" << endl;
else cout << "korney net" << endl;
proverka(x1, x2);
break;
}
case 2: {
double x, a, b;
int swtch;
cout << "Vvedite chislo dlya vibora" << endl;
cout << "SIN-1" << endl; cout << "COS-2" << endl; cout << "POW-3" << endl; cout << "TAN-4" << endl; cout << "FACT-5" << endl;
cin >> swtch;
switch (swtch)
{
case 1: {
cout << "Vvedite x:" << endl; cin >> x;
cout << "sin " << x << " = " << _sin(x);
break;
}
case 2: {
cout << "Vvedite x:" << endl; cin >> x;
cout << "cos " << x << " = " << _cos(x);
break;
}
case 3: {
cout << "Vvedite a:" << endl; cin >> a;
cout << "Vvedite stepen:" << endl; cin >> b;
cout << "pow " << a << " s stepenyu" << b << " = " << _pow(a, b);
break;
}
case 4: {
cout << "Vvedite x:" << endl; cin >> x;
cout << "tan " << x << " = " << _tan(x);
break;
}
case 5: {
cout << "Vvedite x:" << endl; cin >> x;
cout << "FACT! " << x << " = " << _fact(x);
break;
}
default:break;
}
default:break; }
}
}
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