What address will 1 be written to?

Question

assembler

Good afternoon

Judging by this image, if I try to do this:
mov dword [block], 1
And on my computer there will be a processor with a little-endian processor, then it turns out that if I try to read 4 bytes at block address, I will not get one, as I expected, but 16777216? After all, the addresses grow downward, or is the unit still written to the low byte, that is, at the address block + 3?

Answer 1

I seem to understand a little, please correct me if it's wrong - If I had a computer with big-endian, then the unit would be written at the address block + 3, not as I would point to mov dword [block], 1, namely at the address block + 3. In little endian recorded exactly as I would have indicated. Apparently, for this, there is a requirement to clarify the size of the operand of the memory type, because the byte order is different