Website accessibility check, how to check several?

Question

PHP

Hello.
There is a script which checks availability of the server.

function isDomainAvailible($domain)
       {
               //проверка на валидность урла
               if(!filter_var($domain, FILTER_VALIDATE_URL))
               {
                       return false;
               }
               //инициализация curl
               $curlInit = curl_init($domain);
               curl_setopt($curlInit,CURLOPT_CONNECTTIMEOUT,10);
               curl_setopt($curlInit,CURLOPT_HEADER,true);
               curl_setopt($curlInit,CURLOPT_NOBODY,true);
               curl_setopt($curlInit,CURLOPT_RETURNTRANSFER,true);
               //получение ответа
               $response = curl_exec($curlInit);
               curl_close($curlInit);
               if ($response) return true;
               return false;
       }
     ?>

How to make it so that not one site is checked, but several?
Just copying this code twice is not very convenient.

Answer 1

Call the function as many times as you like, you can for convenience in a loop or simply, in order:

isDomainAvailible('http://site1.ru');
isDomainAvailible('http://site2.ru');

Answer 2

Pass multiple domains to the function.
For example, there is an array of 2 sites array('site1','site2');
Just pass the values ​​of the array in the loop

<?php
$domain = array('http://butsw.pp.ua/', 'http://google.com/', 'http://gryazniepisyuni.com/');
foreach ($domain as $url) {
    $is = isDomainAvailible($url);
    if ($is == 1) {
        echo "OK! <br>";
    } else {
        echo "ERR!!!<br>";
    }
}

And the result

Answer 3

Use curl_multi_init:
php.ru/manual/function.curl-multi-init.html