Using a regular expression to get an array between two labels

Question

Regular Expressions

#word1#--start--#word2#word3#dflsjdf#--end--#word4#word5#

Task: Use a regular expression to get an array of words between two marks (start, end) To get
word2, word3, dflsjdf
There can be any number of words.

Answer 1

/--start--#(.*)#--end--/ and then split the result by # symbol

Answer 2

If only with one regular expression, then it can be like this:
/--start--#(?:([^#]*)#)?(?:([^#]*)#)?(?:([^#]*)#)?(?:([^#]*)#)?(?:([^#]*)#)?(?:([^#]*)#)?(?:([^#]*)#)?(?:([^#]*)#)?(?:([^#]*)#)?(?:([^#]*)#)?(?:([^#]*)#)?(?:([^#]*)#)?(?:([^#]*)#)?(?:([^#]*)#)?(?:([^#]*)#)?(?:([^#]*)#)?(?:([^#]*)#)?(?:([^#]*)#)?(?:([^#]*)#)?(?:([^#]*)#)?(?:([^#]*)#)?(?:([^#]*)#)?(?:([^#]*)#)?(?:([^#]*)#)?(?:([^#]*)#)?(?:([^#]*)#)?(?:([^#]*)#)?(?:([^#]*)#)?(?:([^#]*)#)?(?:([^#]*)#)?(?:([^#]*)#)?(?:([^#]*)#)?(?:([^#]*)#)?(?:([^#]*)#)?(?:([^#]*)#)?(?:([^#]*)#)?(?:([^#]*)#)?(?:([^#]*)#)?(?:([^#]*)#)?(?:([^#]*)#)?(?:([^#]*)#)?(?:([^#]*)#)?(?:([^#]*)#)?(?:([^#]*)#)?(?:([^#]*)#)?(?:([^#]*)#)?(?:([^#]*)#)?(?:([^#]*)#)?(?:([^#]*)#)?(?:([^#]*)#)?--end--/
Only now an arbitrary number is no longer obtained, only up to a certain number (here - up to fifty). Well, the result will turn out, let's say, not quite clean - but here it all depends on the language used.

Answer 3

(/--start--#(.*)#--end--/).split("#").toArray(); - one expression