The template argument is a structure type. How can this type be replaced other than #define NEW_TYPE OLD_TYPE?

Question

C++ / C#

Example:

template<typename T> int funcExample(int x, int y) { T s; s.a = x; s.b = y; return s.a + s.b; }

struct Foo{
   int a;
   int b;
};

#define Bar Foo
  
int main()
{
   int absum  = funcExample<Foo>(1, 2);
   std::cout << "sum: " << absum << "\n";
  
   absum  = funcExample<Bar>(3, 4);
   std::cout << "sum: " << absum << "\n";  
}

The fact is that I have a lot of all sorts of Foo, Bar, etc. for code readability. They are exactly the same in appearance, but different in use.
Or I'll make an unreadable code (well, with comments that this is - this is actually that). Or is there a solution that I don't know about. With some pointers, for example.

Answer 1

en.cppreference.com/w/cpp/language/type_alias