Reverse engineering. Modifying the Popup panel?

Question

ARM

My task was to change the values ​​to 20 (on the screenshot), but the best I could do was just remove them...
Screenshot:

I found a piece of disassembled code where, in my opinion, the values ​​I need are exactly:

;-- func. 0118eab0:
0x0118eab0 sub sp, sp, 0x50
0x0118eab4 stp x24, x23, [sp, 0x10]
0x0118eab8 stp x22, x21, [sp, 0x20]
0x0118eabc stp x20, x19, [sp, 0x30]
x2 ,eac0 , 0x40]
0x0118eac4 add x29, sp, 0x40
0x0118eac8 mov x19, x0
0x0118eacc adrp x20, 0x2c0e000
0x0118ead0 ldrb w8, [x20, 0xa1f]
0x0118ead4 tbnz w8, 0eaf0x
0x0118ead8 adrp x8, 0x245f000
0x0118eadc nop
0x0118eae0 ldr w0, [x8, AVAssetExportPresetPassthrough] ; 0x490
0x0118eae4 bl func.00ce5d5c ; sym.func.00ce5d5c
0x0118eae8 movz w8, 0x1
0x0118eaec strb w8, [x20, 0xa1f]
0x0118eaf0 str wzr, [sp, 8]
0x0118eaf4 str xzr, [sp]
0x0118eaf8 mov x0, x19
0x0118eafc movz x1, 0
0x0118eb00 bl func.011071bc ; sym.func.011071bc
0x0118eb04 ldr x8, [x19, 0x88]
0x0118eb08 cbz x8, 0x118ec44
0x0118eb0c ldur x21, [x8, 0x2c]
0x0118eb10 ldr w20, [x8, 0x34]
0x0112
0x0118eb18 ldr w22, [x8, 0x28]
0x0118eb1c adrp x24, 0x2da7000
0x0118eb20 add x24, x24, 0x3c8
0x0118eb24 ldr x0, [x24]
0x0118eb28 ldrb w8, [x0, 0x12f]
0x0118eb2c tbz w8, 1, 0x118eb3c
0x0118eb30 ldr w8, [x0 , 0xe0]
0x0118eb34 cbnz w8, 0x118eb3c
0x0118eb38 bl func.00ce5e64 ; sym.func.00ce5e64
0x0118eb3c mov x0,
x21 0x0118eb40 mov x1, x20
0x0118eb44 mov x2, x23
0x0118eb48 mov x3, x22
0x0118eb4c movz x4, 0
0x0118eb50 bl func.013d4238 ; sym.func.013d4238
0x0118eb54 ldr x8, [x24]
0x0118eb58 ldr x8, [x8, 0xb8] 0x0118eb5c ldur
x2, [x8, 0xc] 0x0118eb60
ldr w3, [x8, 0x14 ] sym.func.013d2ae0 0x0118eb70 str x0, [sp] 0x0118eb74 mov x21, sp 0x0118eb78 str w1, [sp, 8] 0x0118eb7c ldr x20, [x19, 0x98] 0x0118eb80 orr x0, x21, 4 0x0118eb8eb80 .0220d5ec ; sym.func.0220d5ec 0x0118eb8c cbz x20, 0x118ec44 0x0118eb90 mov x1, x0 0x0118eb94 mov x0, x20
0x0118eb98 movz x2, 0
0x0118eb9c bl func.012a33b8 ; sym.func.012a33b8
0x0118eba0 ldr x8, [x19, 0x88]
0x0118eba4 cbz x8, 0x118ec44
0x0118eba8 add x20, x21, 8
0x0118ebac ldr w8, [x8, 0x1c]
0x0118ebb0 ldr x21, [x19, 0x90]
0x0118ebb4 cmp w8, 1
0x0118ebb8 b.hi 0x118ebe8
0x0118ebbc mov x0, sp
0x0118ebc0 movz x1, 0
0x0118ebc4 bl func.0220d5ec ; sym.func.0220d5ec
0x0118ebc8 cbz x21, 0x118ec44
0x0118ebcc mov x1, x0
0x0118ebd0 mov x0,
x21 0x0118ebd4 movz x2, 0
0x0118ebd8 bl func.012a33b8 ; sym.func.012a33b8
0x0118ebdc ldr x19, [x19, 0xa0]
0x0118ebe0 mov x0, x20
0x0118ebe4 b 0x118ec10
0x0118ebe8 mov x0, x20
0x0118ebec movz x1, 0
0x0118ebf02; fundec5ec02; sym.func.0220d5ec
0x0118ebf4 cbz x21, 0x118ec44
0x0118ebf8 mov x1, x0
0x0118ebfc mov x0,
x21 0x0118ec00 movz x2, 0
0x0118ec04 bl func.012a33b8 ; sym.func.012a33b8
0x0118ec08 ldr x19, [x19, 0xa0]
0x0118ec0c mov x0, sp
0x0118ec10 movz x1, 0
0x0118ec14 bl func.0220d5ec ; sym.func.0220d5ec
0x0118ec18 cbz x19, 0x118ec44
0x0118ec1c mov x1, x0
0x0118ec20 mov x0, x19
0x0118ec24 movz x2, 0
0x0118ec28 bl func.012a33b8 ; sym.func.012a33b8
0x0118ec2c ldp x29, x30, [sp, 0x40]
0x0118ec30 ldp x20, x19, [sp, 0x30]
0x0118ec34 ldp x22, x21, [sp, 0x20]
0x0118ec38 ldp x24, x18x01, [
0x018x01 ] add sp, sp, 0x50
0x0118ec40 ret
0x0118ec44 bl func.00ce5ef4 ; sym.func.00ce5ef4

If you use nop on all mov x1, x0 , all values ​​will be lost:



I'm not good at reverse engineering, so if you can help me, I'd be very grateful.