Regular expression does not work correctly

Question

Regular Expressions

On the one hand, everything is eerily trite - you need to allow the user to enter the first and last name in different fields, the conditions are Latin or Cyrillic, dot, space.
a-zdoes not skip the entire Cyrillic alphabet and the parameter ialso does not work with it, moreover, a-z does not represent the entire range of Cyrillic.

I did it tritely: /^([a-zA-Z \.\-]{1,20}|[абвгдеёжзийклмнопрстуфхцчшщъыьэюяАБВГДЕЁЖЗИЙКЛМНОПРСТУФХЦЧШЩЪЫЬЭЮЯ \.\-]{1,20})$/
Everything is cool, but there are situations when this bastard does not take what he needs, and specifically the name "Phoenician" - and eats it in parts, completely - no!

The only thing I do before checking is to process the received data with the function trim(), but the situation does not change even if it is removed.

Help, brothers and sisters!

Answer 1

In PHP in UTF-8, you must use the u modifier Manual
excerpt:
u (PCRE_UTF8)
This modifier turns on additional functionality of PCRE that is incompatible with Perl. Pattern strings are treated as UTF-8. This modifier is available from PHP 4.1.0 or greater on Unix and from PHP 4.2.3 on win32. UTF-8 validity of the pattern has been checked since PHP 4.3.5.
The expression becomes /^([az \.\-]{1,20}|[a-yayo \.\-]{1,20})$/ui

Answer 2

Grenades, you have the wrong system. In .NET, the pattern works for "Phoenician", just checked. Most likely a bug in the code, some left character is missing somewhere.

Answer 3

And ^([a-zA-Z \.\-]{1,20}|[a-zA-Z \.\-]{1,20})$ works great too.

Answer 4

The point in enumerations does not need to be escaped, and the hyphen at the end too (but only if it is at the end).