Python3 os.path.abspath(os.path.dirname(__file__)) returns wrong?

Question

Django

I need to return the very beginning of the site for different OSes,
Google writes that this should return it,
os.path.abspath(os.path.dirname(__file__))
i.e. if the site is located on D: / python_proj / mysite.com
Then it should return this address
But it grows the address of the folder where the script that executes this lies command

Answer 1

Which is absolutely logical. You are asking for the location of the file where you are executing the code: os.path.dirname(__file__). If you need to get the value of the top level address:

• Initialize the constant at the entry point and include it in the required module. OR
  
• Manually specify how many levels up to return from the current file.
  

Answer 2

i.e. if the file is located at D:/python_proj/mysite.com