Python. Iterating over unique values ​​skips values?

Question

Python

Iteration skips 'two' as unique (even though it's not in the checklist) and leaves it for later

def list(lst):
    lst_new = []
    while lst:
        lst_temp = []
        for i in lst:
            if i not in lst_temp:
                lst_temp.append(i)
                lst.remove(i)
        lst_new += lst_temp
    return lst_new

l = list(["one", "one", "two", "two", "three", "three", "four", "one"])
d = ["one", "two", "three", "four", "one", "two", "three", "one"] #должно быть так
print(l)
print(d)

Answer 1

Because it is not necessary to change the iterable collection.

Answer 2

You read the list and change it at the same time.
In general, you have a strange design.

Answer 3

Do not use names that are the same as built-in types.
Changing the iterated list is also a bad idea, when an element is removed, the remaining elements change their position, but the loop takes the next element, regardless of whether the order has changed or not, that's why there are gaps.