Python: How to run a module as a script in a package?

Question

Python

There is an architecture:
/
- readme.md
- name_of_project
-- bin
-- packages
--- foobar
----- __init__.py
----- FoobarModule.py
--- logs
----- __init__.py
-- --- LogsModule.py
Contents of
FoobarModule.py

import packages.logs.LogsModule
#some code

if __name__ == '__main__':
   #do some work with this module

I run:

python root/name_of_project/packages/foobar/FoobarModule

but the error is thrown that it cannot find the LogsModule module.
This is logical, since there is no way to it. Now, if I ran from the root - everything works.
How to run the FoobarModule as a standalone script to execute the code in if __name__ == '__main__': ?
Help to deal with the paths in the project or throw the dock how to properly organize everything in the project.
Questions:
-- all paths must be from packages? if the module refers to a module in the current package, then the path is relative.
-- All commands to be run must be at the packages level, so that there are no problems?
-- if I want each module in the package to contain the __name__=='__main__' blob and test itself, how do I run that module separately? there is an option to run the project from the root:python -m packages.foobar.FoobarModule

Answer 1

from packages.logs import LogsModule

?
In general, a slightly strange approach, but at least it is worth creating a script at the root and calling everything else inside it.

Answer 2

I would say that it would be better if you wrote unittests instead of manually running each file,
this is both more useful and easier