Python default options?

Question

Python

I ran into an interesting problem.

def change(proxy=get()['proxy'], gmail=get()['gmail'], password=get()['password'], json_active=os.path.isfile(JSON_PATH)):
    ''' "change" changes the values ​​of config.json '''
    print(json_active)
    print(os.path.isfile(JSON_PATH))
    
    config = {
        'proxy': proxy,
        'gmail': gmail,
        'password': password,
        'json_active': json_active
    }

    with open(f'{os.getcwd()}\\config\\config.json', 'w') as file:
        json.dump(config, file, indent=1)

I have a change function, the result of the isfile method from the os module is passed to the json_active parameter.
This method checks if the file exists and returns True or False depending on this.

Now, I'm importing my change function into my main.py file.

def main():
    clear_terminal.clear()

    config.change()
    data = config.get()

    flag = input('>>> ')

    if flag == '1':
        
        USER_EMAIL = input('Your Gmail: ')

        number_combinations = email_combinate.combinate(USER_EMAIL)
        print(f'JSON generated, size: {number_combinations}')
        input('Press ENTER to continue')

        main()

When you run the main() function from the main.py file somewhere at the start, the change function is called. And config.json changes.
So, if a file is created while main.py is running, then the json_active parameter in the change function is still False.

But, if the change function is run without importing, then everything works out with a bang.

There are suspicions that Python remembers the default parameter values ​​and assigns the last parameter value to them the next time, and all this because of the compiled .pyc files. Could this be?

Answer 1

Default parameter values ​​are defined only once at the time of script execution or module import.