Promise: How to pass parameter then(param) further down the chain?

Question

JavaScript

Provided that in the first then it is necessary to return Promise. Without it, it is clear how to convey.

...
.then(function(param1) {
  ...
  return Promise;
})
.then(function(param2) {
  // здесь нужно иметь доступ к значению param1 из предыдущего then
})

Answer 1

.then(function(param1) {
  ...
  return Promise.all([
    Promise.resolve('val1'),
    param1
  ]);
})
.then(function(arr) {
  var param2 = arr[0]
    , param1 = arr[1] 
})

Answer 2

Pass it as an argument when resolving a promise:
jsfiddle.net/koceg/b23xgbLy/1

Answer 3

What about

var param1;
// ...
.then(function(p1) {
    param1 = p1;
    // ...
    return Promise;
})
.then(function(param2) {
  console.log(param1, param2);
})

Answer 4

Looks like I found a way:

...
.then(function(param1) {
    ...
    Promise.then(function(param2) {
        return {param1: param1, param2: param2};
    });
    return Promise;
})
.then(function(params) {
    // params.param1, params.param2
})