Php under windows 7 in cli mode does not see arguments?

Question

PHP

php 5.3 CLI
windows 7
I want to call php scripts just by calling the file name.
I do so

assoc .php=phpfile<br/>
ftype phpfile=&quot;c:\php\php.exe&quot; -f &quot;%1&quot; -- %~2<br/>

I try to call the script simply by the file name with the "helo" argument:
touch.php helo<br/>
Dump $argv:

array(1) {<br/>
 [0]=&gt;<br/>
 string(26) &quot;C:\hg\PHPScripts\touch.php&quot;<br/>
}<br/>

I call the script in full form:
c:\php\php.exe touch.php helo<br/>
Dump $argv:

array(2) {<br/>
 [0]=&gt;<br/>
 string(9) &quot;touch.php&quot;<br/>
 [1]=&gt;<br/>
 string(4) &quot;helo&quot;<br/>
}<br/>

That is, the arguments of the script call are visible to it only when it is called in full form, with the path to the interpreter. Is it curable?

Answer 1

look Process Explorer'om command line.
To do this, organize an infinite loop (30 seconds by default timeout :) ).

Answer 2

Try the following calls:
ini_get('register_argc_argv')
What do both results show?

Answer 3

In both cases, it shows the value "1".