Passing a numeric value (int) to the snippet. How?

Question

PHP

Good afternoon!
There is a chunk with content (wayfinder output):

and there is a snippet:

$sql = "SELECT * FROM {$modx->getTableName('modResource')} WHERE parent = $parent";
$q = $modx->prepare($sql);
$q->execute(array(0));
$arr = $q->fetchAll(PDO::FETCH_ASSOC);
echo count($arr);

The bottom line is that a string is being passed. When trying to convert (int), the $parent variable becomes equal to 0. Without conversion, it still returns 0.
How to be?

Answer 1

Everyone, back off. Wayfinder gives out a kind of crooked ID. How exactly, too lazy to understand.
In general, you have to give