Parser returns html instead of json?

Question

Python

Wrote an instagram parser to get the id and username of a user from a link.
Here is the code:

href = 'https://instagram.com/instagram/'
response = requests.get(href + '?__a=1')
user = json.loads(response.text) #получаем json, в котором указан id и username
user_id = user['graphql']['user']['id'] #получаем id 
username = user['graphql']['user']['username'] #получаем username
print(user_id, username) #выводим id и username

The script works in the Django site view when an ajax request is sent. Everything works fine on the locale - I get json and work further, and on a flooded site it gives out html. I decided to render the html and saw that it renders the instagram login page instead of the user page. What could be causing this error?

Answer 1

With the fact that Instagram blocks parsers.