Override operator() to access class member?

Question

C++ / C#

Let's say I have such a class (I removed everything superfluous for clarity):

class Window{
public:
  Graphics *g;
}

For example, I create somewhere In order to call the function of the g object, I need to write tediously and only then write the desired function. This is bad at least because my g can be easily changed outside the class. But making it private is not a good idea, because then you have to write some kind of layer to call each function, and there are about a hundred of them, and even all with overloads. And I thought: is it possible to somehow cleverly redefine operator () so that these lines are equivalent:Window myWindow();myWindow.g->

myWindow.g->Clear(Color::White);
myWindow(Clear(Color::White));

That is, roughly speaking, to forward the methods of the g object to your class. Is it real at all? Well, or at least something similar, so that the code is more secure and compact.

Answer 1

Maybe you'd be fine with inheriting your Window from Graphics?
The effect of inheritance is exactly what you want to get in other ways.

Answer 2

class Window{
public:
  Graphics& operator * () const { return *g; }
  Graphics* operator -> () const { return g; }
private:
  Graphics *g;
}

...

window->Clear(Color::White);